带分数的二元一次方程组怎样解 (2x+y)/4-[来自5(x-2y)]/3=6 [3(2x+y)]/4-(x-y)/3=4

带分数的二元一次方程组怎样解 (2x+y)/4-[来自5(x-2y)]/3=6 [3(2x+y)]/4-(x-y)/3=4

(2x+y)/4-[5(x-2y)]/3=6[3(2x+y)]陈支响迫旧环数磁抓云/4-(x-y)/3=4

(2x+y)/4-[5(x-2y)]/3=4

6[3(2x+y)]/4-(x-y)/3=4

俩个方程分别化简:

-14x+43y=48

52x+29y=24

俩式连列即可求解

标签：2x,带分数,2y