求出下列图形中x的值.
$\left ( {1} \right )$依题意得
${x}^{\circ }+5{0}^{\circ }+9{0}^{\circ }=18{0}^{\circ }$
${x}^{\circ }+14{0}^{\circ }=18{0}^{\circ }$
${x}^{\circ }=4{0}^{\circ }$
$x=40$
$\left ( {2} \right )$依题意得
${x}^{\circ }+{x}^{\circ }+4{0}^{\circ }=18{0}^{\circ }$
$2{x}^{\circ }+4{0}^{\circ }=18{0}^{\circ }$
$2{x}^{\circ }=14{0}^{\circ }$
${x}^{\circ }=7{0}^{\circ }$
$x=70$
$\left ( {3} \right )$依题意得
${x}^{\circ }+\left ( {x+10} \right )^{\circ }=\left ( {x+70} \right )^{\circ }$
${x}^{\circ }+{x}^{\circ }+1{0}^{\circ }={x}^{\circ }+7{0}^{\circ }$
$2{x}^{\circ }+1{0}^{\circ }={x}^{\circ }+7{0}^{\circ }$
${x}^{\circ }=6{0}^{\circ }$
$x=60$
$\left ( {4} \right )$依题意得
${x}^{\circ }+9{0}^{\circ }+9{0}^{\circ }+\left ( {x+10} \right )^{\circ }=36{0}^{\circ }$
${x}^{\circ }+9{0}^{\circ }+9{0}^{\circ }+{x}^{\circ }+{10}^{\circ }=36{0}^{\circ }$
$2{x}^{\circ }+19{0}^{\circ }=36{0}^{\circ }$
$2{x}^{\circ }=17{0}^{\circ }$
${x}^{\circ }={85}^{\circ }$
$x=85$
$\left ( {5} \right )$依题意得
${x}^{\circ }+\left ( {x+20} \right )^{\circ }+7{0}^{\circ }+{x}^{\circ }+\left ( {x-10} \right )^{\circ }={540}^{\circ }$
${x}^{\circ }+{x}^{\circ }+{20}^{\circ }+7{0}^{\circ }+{x}^{\circ }+{x}^{\circ }-{10}^{\circ }={540}^{\circ }$
$4{x}^{\circ }+8{0}^{\circ }={540}^{\circ }$
$4{x}^{\circ }={460}^{\circ }$
${x}^{\circ }={115}^{\circ }$
$x=115$
标签：图形,下列
